Question

In a nuclear experiment particle of unknown mass moving at 460 km/s undergoes head on elastic collision with carbon. nucleus moving at 220 km/s after collision carbon nucleus Continuous in a same direction at 340km/s. Find mass and unknown final velocity of​

Answer 1

Explanation:

Here, initial velocity of the unknown particle, u1=469 km/s

initial velocity of the carbon nucleus, u2=220 km/s

final velocity of the unknown particle, v1=?

final velocity of the carbon nucleus, v2=340 km/s

mass of the unknown particle, m1=?

mass of the carbon nucleus, m2=12 u=0.012 kg

Using the equation, v2=2 m1 u1m1+m2+(m2−m1)u2m1+m2

We get,

340=2 m1×460m1+0.012+(0.012−m1)×220m1+0.012340=920 m1m1+0.012+2.64−220 m1m1+0.012340=700 m1+264m1+0.012340 m1+4.08=700 m1+264or, m1=0.722 kg

Now,

v1=m1−m2m1+m2u1+2 m2m1+m2u2 =0.722−0.0120.722+0.012×460+2×0.0120.722+0.012×220 =452.16 km/s

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Answer 2

Answer:

butter fly

Explanation:

Find the value of

15/26

15/16

1/4

25/26