In a number of two digits, the ratio of the digit in the tens place and the digit in the
unit place is 3 : 1. If 3 is added to three times the sum of the digits, then the opposite
number is formed. Find the number.
Answers
Answer:
In a number of two digits, the ratio of digit in tens place and in unit place is 3:1. If 3 is added to three times of sum of its digits then the opposite number is formed. What is the initial number?
If the unit digit is than the whole number is () this means as would give and would make for a digit number. The sum of the digit is still so we have (as ) this leads to a non-digit solution for , ok brute force
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Yep no such number.
61 views · Answer requested by Sanjay Thapa Chhetri
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Other Answers

Gary Underwood, M.S. in Computer Science; work in medical NLP
Answered March 16 · Author has 611 answers and 171.9K answer views
You can list them and try them out. If ratio is 3:1, then possible values are 31, 62, and 93. 9+3=12, 12*3 = 36, 36+3=39 which is 93 in reverse (assuming that is what ‘opposite’ number means. Normally opposite in mathematics is the negative).
You could also do this with equations. Let X be the 10s digit and Y be the ones digit. So the number is 10X+Y.
X = 3*Y (ratio).
3*(X+Y)+3 = 10*Y + X.
3* (3*Y +Y) + 3 = 10*Y + 3*Y (plug in X = 3*Y)
12Y + 3 = 13Y
Y = 3, X = 9.
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Partha Chattopadhyay, Taught while teaching and still practicing
Answered March 16 · Author has 2.4K answers and 2.4M answer views
Let the digit in tens place be x and the digit in units place be y. Then the initial number is . It is given that
If 3 is added to three times of sum of the digits then the opposite number is formed which means
But from (1), . So,
Again from (1),
Hence, the initial number is
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Neil Morrison, BA Mathematics, The Open University
Answered March 16 · Author has 5.8K answers and 5.8M answer views
No need to be clever here - the list of possibles is very short!
The fact that it is only two digits and that there is a 3:1 ratio means it can only be 31, 62 or 93. (with the addition of maybe 13, 26, 39 if you allow the ratio to be the other way around)
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Answer:
Let the digit in tens place be x and the digit in units place be y. Then the initial number is 10x+y . It is given that x:y=3:1⇒x=3y.....(1)
If 3 is added to three times of sum of the digits then the opposite number is formed which means 3(x+y)+3=10y+x⇒10y−2x−3y=3⇒7y−2x=3..(2)
But from (1), x=3y . So, (2)⇒y=3
Again from (1), x=3y⇒x=9
Hence, the initial number is 10(9)+3=90+3 =93.
(mark me as the brainliest)