Math, asked by shakthisaravanan, 11 months ago

In a nursery 37 plants have arranged in the first row ,35 in the second , 33 in the third and so on. If there are 5 plants in the last row how many plants are there in the nursery?

Answers

Answered by SoniaAbhi
2

Step-by-step explanation:

First Row=37

Second Row=35

Third Row=33

Last Row=5

Total in the nursery

37+35+33+5=110 plants

So your answer is 110

Answered by sunnysinghdollysingh
2

Answer:

total 358 plants

Step-by-step explanation:

to find sum of n odd numbers

(1 to 37)

add 1 to 37 =38

then divide by 2=19

now square of 19 gives answer =361

now remove 3 plants because we calculated from 1 to 37 not from 5 to 37

that gives reqd answer 358

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