Question

in a one day cricket match,a batsman hits the boundary 8 times out of 48 balls he plays .Find the probability that he does not hit the boundary.​

Answer 1

Answer:

5/6

Step-by-step explanation:

probability of hitting boundaries =8/48=1/6

probability of not hitting boundaries= 40/48=5/6

Answer 2

Answer:

If in 48 balls, he hits 8 boundaries, he doesn't hit 40 boundaries.

So, the probability of him not hitting a boundary is 40/48

Therefore, the probability of the batsman not hitting a boundary is 5/6.

Hope this helps.