In a one day international cricket match, considering no extras (no wides, no 'no' balls, etc.) and no overthrows. What is the maximum number of runs that a batsman can score in an ideal case? Note: "Here we assume ideal and little practical scenario. We assume that batsman cannot run for more than 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoretically) in a ball, as far as opposite team does not catch the ball."
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Answers
1800
Explanation:
a cricket one day match is 50 overs
one over is 6 balls
hence total playable balls is 50×6=300
so now a batsman can theoretically get 6 runs per ball
therefore the most possible runs are 300×6=1800
1653 runs would be the highest a batsman might achieve in an ideal match.
The hitter should attempt to knock a six on each ball. The strike, however, will change in the following over and go to his partner if he knocks six on the first ball of the over, as is the case according to cricket rules. The best he can do with the final ball is score three runs in order to maintain his attacking position during the next over.
This means that he can score a total of 33 runs in each over: 6*5 + 3=33.This will go on till the 49th overs is up. He can knock a six with the final ball of the over because it will be the final ball of the innings.
Therefore, the last over's total runs would be as follows: 6*6=36
So, the most runs he could possibly make are:
(33 runs*49 overs) + 36 = 1617 + 36 = 1653
Thus, 1653 runs would be the highest a batsman might achieve in an ideal match.
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