Question

in A.P 6th termis 12 and 8th term is 22 then 2nd term is​

Answer 1

Answer:

5n-18

Step-by-step explanation:

Given, a,=a+5d=12-

And ag=a+7d=22

Eq(2)-Eq(1)=2d=10 d=10/2

d=5

4.0

Substituting d=5 in(1),

a+5(5)=12 a=12-25

a=-13

49

votes

-(1) (2)

Therefore, the second term of the AP,az=a+d=(-13)+5=-8

And nth term of the AP=a+(n-1)d =(-13)+(n-1)5

=(-13)+5n-5

=5n-18

Answer 2

Answer:

the second term is -4/3

Step-by-step explanation:

6th term = 12

8th term = 22

let the first term be 'a'

let the common difference be 'd'

therefore ,

a6 = a + 5d ............(i)

a8 = a + 7d ..............(ii)

on subtraction :-

a + 7d = 22

a + 5d = 12 a + 5*10/3 = 12

(-). (-). (-) a = 12 - 50/3

_____________. a = -14/3

3d = 10

d = 10/3

therefore , second term a2 = a + d = -14/3 + 10/3 = -4/3

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