in A. P a3=10 and a8=40 thn find common difference
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Answered by
5
Answer:
Step-by-step explanation:
A+(3-1)d = 10
A+2d=10
A=10-2d
A+(8-1)d=40
A+7d=40
10-2d+7d=40
5d=30
D=6
santrupti:
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Answered by
1
Given:
In an A.P.
a3=10,a8=40
an=a+(n-1)d ...... by formula
a3=a+2d
10=a+2d
a+2d=10 .......eq1
a8=a+7d
40=a+7d
a+7d=40......eq2
sub eq1 - eq2
a+2d=10
a+7d=40
-__________
-5d=-30
d=-30/-5
d=6
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