Question

In a p-n junction having depletion layer of thickness 10⁻⁶ m the potential across it is 0.1 V. The electric field is(a) 10⁷ V/m(b) 10⁻⁶ V/m(c) 10⁵ V/m(d) 10⁻⁵ V/m

Answer 1

E=V/d

E=0.1/10^-6

E=10^5V/m

Answer 2

The electric field is $10^5\ V/m$.

Explanation:

It is given that,

Thickness of the p-n junction, $d=10^{-6}\ m$

Electric potential, V = 0.1 V

We need to find the electric field. The relation between the electric field and electric potential is given by :

$E=\dfrac{dV}{dl}$

or

$E=\dfrac{V}{l}$

$E=\dfrac{0.1\ V}{10^{-6}\ m}$

$E=10^5\ V/m$

So, the electric field is $10^5\ V/m$. Hence, this is the required solution.

Learn more,

Electric field,

https://brainly.in/question/8464331