Question

In a pair of fractions, fractions a is twice the fraction b and the product of two fractions is 6/25. What is the value of fraction a?

Answer 1

Step-by-step explanation:

let fraction b be x

a be 2x

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2x*x =6/25

2x^2=6/25

x^2=3/25

x=√3/25

Answer 2

The value of Fraction a is $\frac{2\sqrt{3}}{5}$

Step-by-step explanation:

Let the Fraction b be x

We are given that fractions a is twice the fraction b

So, So, Fraction a = 2x

We are given that the product of two fractions is 6/25

So, $x(2x)=\frac{6}{25}\\2x^2=\frac{6}{25}\\x^2=\frac{3}{25}\\x=\sqrt{\frac{3}{25}}\\x=\frac{\sqrt{3}}{5}$

So, Fraction a = $2x=2(\frac{\sqrt{3}}{5})=\frac{2\sqrt{3}}{5}$

Hence The value of Fraction a is $\frac{2\sqrt{3}}{5}$

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If sum and product of two numbers are 24 and 128 respectively find the numbers

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