Question

In a parallel plate capacitor , plate area is 100 cm2 and plate separation is 1mm. A charge of 0.10 µC comes on the plate of capacitor if its plates are connected to 100 Volt . Find the dielectric constant of the medium between plates​

Answer 1

Answer:

This is a simple problem in which we have to calculate the value of dielectric constant (εr) that is used in different capacitors. The procedure for the dielectric constant calculation is given in explanation.  

Explanation:

Given data:

Plate area = A = 100 cm2 = 100x10-4 m2

Separation = d = 1 mm = 0.001 m

Charge = Q = 0.10 µC

Voltage = V = 100 V

k = εr = Dielectric constant = ?

εo = 8.854 x10-12 F/m

As we know that the formula of capacitance of capacitor is

C=(k*εo*A)/d

By rearranging the above equation

k=(Q*d)/(V*εo*A)

Now putting the respective values

$k=(0.10*10^{-6}*0.001)/(100*8.854*10^{-12}*100*10^{-4})$

k=100x-12/8.854x10-12

k=11.3

OR

εr = Dielectric constant = 11.3