In a parallel plate capacitor, the capacitance increases by introducing a
dielectric in plates from
2uF to 20uF. The value of dielectric constant is:
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1
Answer:
Initial capacitance is given as C=10μF
⇒C=
d
ε
0
A
=10μF
New arrangement acts as two capacitors C
1
and C
2
connected in parallel.
Thus capacitance of each part C
1
=
d
k
1
ε
0
A
1
and C
2
=
d
k
2
ε
0
A
2
Equivalent capacitance of parallel combination C
p
=C
1
+C
2
=(k
1
+k
2
)
d
ϵ
0
(A
1
+A
2
)
⟹ C
p
=(k
1
+k
2
)
2d
ϵ
0
A
(∵A
1
=A
2
=
2
A
)
Thus C
p
=(2+4)×
2
10
=30μF
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