Question

In a parallelgram ABCD A = (3x+12) and B = (2x-32) then find value of x and C D​

Answer 1

Let The measures of two adjacent angles of parallogrom is 3x+12 and 2x-32.

$\underline{\sf{\green{Given}}}$

• Two adjacent angles = 3x+12 and 2x-32.

$\underline{\green{\sf{To \ Find}}}$

• Value of x and Angle C and D

$\underline{\sf{\green{Step~ By~Step~ Explanation}}}$

It is Given that Two adjacent angles of parallogrom is 3x+12 and 2x-32

We Know That

$\text{Sum of Two adjacent angles of parallogrom is \: 180°}$

$→\tt \: 3x + 12 + 2x - 32 = 180$

$→\tt \: 5x - 20= 180$

$→\tt \: 5x = 180 + 20$

$→\tt \: 5x = 200$

$→\tt \: x = 200 \div 5$

$~~\tt \: x = 40$

• $\sf{Angle~ A=3×40+12=120+12=\green{132°°}}$
• $\sf{Angle~ B=2x-32=2×40-32=80-32=\green{48°}}$
• $\sf{Angle~ C=A=\green{132°}~~~~~~~~~~~~~Opposite~ Angle ~Are ~Equal ~In~ Parallelogram}$
• $\sf{Angle~ D=B=\green{48°}~~~~~~~~~~~Opposite~ Angle ~Are ~Equal ~In~ Parallelogram}$

Verification

$\text{Sum of all Angles in A parallelogram is 180°}$

$\therefore \sf \angle A+\angle B+\angle C+\angle D= 180°$

$\sf 132°+48°+132°+48°= 180°$

$\sf 180°= 180°_{\orange{Verified}}$

Answer 2

Answer:

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