in a parallelogram AB CD, angle d=112digree find angle A and angle B
Answers
Answer:
Angle B = Angle D =112° (alternate angles)
Let Angle A= Angle C = x ( alternate angles)
in parallelogram by angle sum property,
112 + 112 + x + x = 360°
2x = 360-224
x= 126/2
x = 63°
Angle A = x = 63°
A ____________ B
/ / C /____________/D
Answer:
In a parallelogram the sum of the sides is 180 degree.
therefore , according to the question
angle D is opposite to angle C
hence, value of angle C = 180-(angle D)
= 180-112
= 68
Like that angle A is also opposite to angle D .
then value angle A is also 68 degree.
hence value of angle B = 360-(112+68+68)
= 112 degree.
so, angle A= 68 degree and angle B = 112