Question

In a parallelogram ABC, if angleA=(2x+25)and angleB=(3x-5), find the value of x

Answer 1



Simran asked in Math

In a parallogram ABCD, if angleA=(2x+25)0 and angleB = (3x-5)0 , find the value of x and the measure of each angle of the parallelogram

 2

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Yash Mathankar answered this
1330 helpful votes in Math, Class XII-Science

In parallelogram ABCD, AD will be parallel to BC. So,

Angle A + Angle B = 180o [Consecutive interior angles)

(2x + 25)o + (3x - 5)o = 180o

5x + 20o = 180o

5x = 160o

x = 32o

Therefore,

Angle A = (2x + 25)o = {2(32) + 25}o = 89o

Angle B = 180o - Angle A = 180o - 89o = 91o

Angle C = Angle A = 89o

Angle D = Angle B = 91o

Answer 2

According to angle sum property of parellelogram....sum of adjacent is equal to 180°

A & B are adjacent angle
so,

2x+25+3x-5=180
5x+20=180
5x=180-20
5x=160
x=32