In a parallelogram ABCD,
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In parallelogram ABCD
Opposite angles are parallel
if A=45 then C=45=90
now,
sum of the area of parallelogram =360
A+B+C+D=360
45+B+45+D=360
90+B+D=360
B+D=360-90
=270
NOW THERE ARE TWO ANGLES THEREFORE IT IS DIVIDED BY 2
B+D=270/2
=135
THEREFORE.,
ANGLE B=135
D=135
ANS-A=45,B=135,C=45,D=135
Opposite angles are parallel
if A=45 then C=45=90
now,
sum of the area of parallelogram =360
A+B+C+D=360
45+B+45+D=360
90+B+D=360
B+D=360-90
=270
NOW THERE ARE TWO ANGLES THEREFORE IT IS DIVIDED BY 2
B+D=270/2
=135
THEREFORE.,
ANGLE B=135
D=135
ANS-A=45,B=135,C=45,D=135
Answered by
4
ANSWER
A = 45°
A = 45°B = 135°
A = 45°B = 135°C = 45°
A = 45°B = 135°C = 45°D = 135°
STEP BY STEP EXPLANATION
In the given parallelogram ,
A = 45°
In a parallelogram opposite angles are equal
so,
A = C = 45°
and also
sum of adjescent sides of a parallelogram = 180
so,
A + B = 180°
45° + B = 180°
B = 180° - 45°
B = 135°
similarly,
B = C = 135° [opposite angles]
so,
A = 45°
B = 135°
C = 45°
D = 135°
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