Question

In a parallelogram ABCD 2∆A= 3∆B. find all the angles of a parallelogram ABCD.​

Answer 1

Step-by-step explanation:

Let ∠B=x

∠A=3∠B=3x

AD∣∣BC

∠A+∠B=180

o

3x+x=180

o

⇒4x=180

o

⇒x=45

o

∠B=45

o

∠A=3x=3×45=135

o

And ∠B=∠D=45

o

Opposite angles of parallelogram are equal

∠A=∠C=135

o

Opposite sides of parallelogram are equal.

AB=CD

5x−7=3x+1

⇒5x−3x=1+7

⇒2x=8

⇒x=4

CD=3×4+1=13

Hence 135

o

,45

o

,135

o

and 45

o

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