In a parallelogram ABCD 2∆A= 3∆B. find all the angles of a parallelogram ABCD.
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Step-by-step explanation:
Let ∠B=x
∠A=3∠B=3x
AD∣∣BC
∠A+∠B=180
o
3x+x=180
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⇒4x=180
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⇒x=45
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∠B=45
o
∠A=3x=3×45=135
o
And ∠B=∠D=45
o
Opposite angles of parallelogram are equal
∠A=∠C=135
o
Opposite sides of parallelogram are equal.
AB=CD
5x−7=3x+1
⇒5x−3x=1+7
⇒2x=8
⇒x=4
CD=3×4+1=13
Hence 135
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,45
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,135
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and 45
o
.
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