in a parallelogram ABCD 2 points p and q are taken on diagonal BD such that DP equal to BQ show that a p c q is a parrlelogram a parallelogram
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Answer:
in a parallelogram ABCD 2 points p and q are taken on diagonal BD such that DP equal to BQ show that a p c q is a parrlelogram a parallelogram
Step-by-step explanation:
in a parallelogram ABCD 2 points p and q are taken on diagonal BD such that DP equal to BQ show that a p c q is a parrlelogram a parallelogram
Question-
In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP =BQ (see fig). show that-
- ∆APD ≅ ∆CQB
- AP = CQ
- ∆AQB = ∆CPD
- AQ = CP
- APCQ is a parallelogram.
Answer-
We have a parallelogram ABCD, BD is the diagonal and points P and Q are such that PD = QB
(i) Since, AD || BC and BD is a transversal.
∴ ∠ADB = ∠CBD [ ∵ Alternate interior angles are equal]
⇒ ∠ADP = ∠CBQ
Now, in ∆APD and ∆CQB, we have
AD = CB [Opposite sides of a parallelogram ABCD are equal]
PD = QB [Given]
∠ADP = ∠CBQ [Proved]
∴ ∆APD ≅ ∆CQB [By SAS congruency]
(ii) Since, ∆APD ≅ ∆CQB [Proved]
⇒ AP = CQ [By C.P.C.T.]
(iii) Since, AB || CD and BD is a transversal.
∴ ∠ABD = ∠CDB
⇒ ∠ABQ = ∠CDP
Now, in ∆AQB and ∆CPD, we have
QB = PD [Given]
∠ABQ = ∠CDP [Proved]
AB = CD [ Y Opposite sides of a parallelogram ABCD are equal]
∴ ∆AQB = ∆CPD [By SAS congruency]
(iv) Since, ∆AQB = ∆CPD [Proved]
⇒ AQ = CP [By C.P.C.T.]
(v) In a quadrilateral APCQ,
Opposite sides are equal. [Proved]
∴ APCQ is a parallelogram.