In a parallelogram ABCD, A = 100
°
find the angle C
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Answered by
0
Answer:
In a parallelogram angle A + B = 180° [co-interior angles]
100 + B = 180°
B = 80°
Since, opposite angles of a parallelogram are equal
Angle B = D = 80°
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Answered by
2
Answer:
look below
Step-by-step explanation:
if ABCD is a parallelogram the,
∠B = 100°
∴ ∠D = 100°
and,
∠A = ∠C = ∠x ( we have let ∠A and ∠C as ∠x )
since opposite angles of a parallelogram is equal.
and,
∠A +∠B + ∠C +∠D = 360°
since angle sum property of a parallelogram is 360°
∠x + ∠x + 100° + 100° = 360°
⇒2∠x + 200° = 360°
⇒2∠x = 360° - 200°
⇒2∠x = 160°
⇒∠x = 160/2
⇒∠x = 80°
therefore ∠A = 80° and ∠C = 80°
I hope that this will help you and until next time take care
Thank youuu! :)
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