Question

In a parallelogram ABCD; ∠A= (2x + 25) and ∠B= (3x – 5). Find the value of x. Therefore, find the value of ∠A and ∠B.

tell me fast step by step I make brilentlist ​

Answer 1

In parallelogram, the sum of adjacent angles is 180°

Therefore,

∠A + ∠B = 180°

(2x + 25) + (3x – 5) = 180°

2x + 3x + 25 – 5 = 180°

5x + 20 = 180°

5x = 180° – 20

5x = 160°

x = 160°/5

x = 32

∠A = (2x + 25)

= 2 * 32 + 25

= 89

∠B = (3x – 5)

= 3 * 32 – 5

= 96 – 5

= 91

Hence, ∠A is 89 and ∠B is 91.

____________________

Mark my answer as brainliest. :)

Answer 2

Step-by-step explanation:

We know that the opposite angles are equal in a parallelogram Consider parallelogram ABCD So we get ∠ A = ∠ C = (2x + 25) o ∠ B = ∠ D = (3x – 5) o We know that the sum of all the angles of a parallelogram is 360o So it can be written as ∠ A + ∠ B + ∠ C + ∠ D = 360o By substituting the values in the above equation (2x + 25) + (3x – 5) + (2x + 25) + (3x – 5) = 360o By addition we get 10x + 40o = 360o By subtraction 10x = 360o – 40o So we get 10x = 320o By division we get x = 32o Now substituting the value of x ∠ A = ∠ C = (2x + 25) o = (2(32) + 25) o ∠ A = ∠ C = (64 + 25) o By addition ∠ A = ∠ C = 89o ∠ B = ∠ D = (3x – 5) o = (3(32) – 5) o ∠ B = ∠ D = (96 – 5) o By subtraction ∠ B = ∠ D = 91o Therefore, x = 32o, ∠ A = ∠ C = 89o and ∠ B = ∠ D = 91o.Read more on Sarthaks.com - https://www.sarthaks.com/725737/parallelogram-abcd-and-find-the-value-and-the-measure-of-each-angle-of-the-parallelogram