In a parallelogram ABCD, ∠A = 62o . Fing the measures of the other angles.
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If A=62o , then C=62o (vertically opposite angles)
Therefore A + B = 180o
B = 118o (angle on the same side of the transversal)
If B = 118o , then D = 118o (vertically opposite angles)
Therefore, B=118o , C=62o , D=118o
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