In a parallelogram ABCD, ∠A = x°, ∠B = 3x° + 60°. Find x, ∠C, ∠D.
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Answered by
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Answer:
here coneA+cone B=180°
x°+3x°+60°=180°
4x°=180°-60°=120°
x=120/4°=30°
cone C=30°
come D=3x°+60°
=3.30°+60°=90°+60°=150°
Answered by
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Answer:
∠C= 45° and ∠D= 135°
Step-by-step explanation:
You must know that adjacent sides of parallelogram are supplementary and opposite side of the parallelogram are congruent to solve this question.
(supplementary means that sum of the two angles is 180°)
Considering the name of the given parallelogram, ∠A and ∠B are adjacent angles.
hence, ∠A+∠B =180°
x + 3x = 180°
4x = 180°
x = 45°
hence ∠A= x = 45°
∠B= 3x = 3x45 = 135°
now opposite sides are congruent,
so, ∠A = ∠C = 45°
and ∠B = ∠D = 135°
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