Question

In a parallelogram ABCD, AB=10cm and AD=6cm. The angle bisector of angle A meets DC at E. AE and BC produced to pt F . Find the length of CF​

Answer 1

Answer:

6cm

Step-by-step explanation:

CE parallel AB on producing AE and BC at F

by midpoint theorem,

CE=1/2AB; CE=5cm

now, by BPT,

CF/BF=CE/AB

CF/6+CF=5/10

CF=6cm