Question

In a parallelogram ABCD, AB=16cm. The altitude corresponding to side AB and AD are respectively 8cm and 10cm, then find the length of AD

Answer 1

area of parallelogram. = B*H=16*8

= 128

given , AD = 10

so H = Area÷B

so, 128÷10

so answer is 12. 8

Answer 2

The length of AD=12.8 cm

Step-by-step explanation:

In parallelogram ABCD

AB=16 cm

Altitude corresponding to side AB,h=8 cm

Altitude corresponding to side  AD,h'=10 cm

Area of parallelogram=$Base\times height$

Using the formula

Area of parallelogram ABCD=$AB\times h=16\times 8 cm^2$

Again ,

Area of parallelogram=$AD\times h'$

Area of parallelogram=$AD\times 10$

$16\times 8=AD\times 10$

$AD=\frac{16\times 8}{10}=12.8 cm$

The length of AD=12.8 cm

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