In a parallelogram ABCD, AB =18cm, BC=12cm, AL perpendicular to DC and AM perpendicular to BC.
If AL=6.4 cm, find the length of AM
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Step-by-step explanation:
This can be done with concept of similarity of triangles.
ABCD is a parallelogram
So angle B=Angle D
Also BC=AD= 12cm
In ΔADL and ΔABM
angle D= Angle B (proved)
angle ALD = angle AMB (each 90 degrees)
Therefore Δ ADL similar to Δ ABM
AL/AM = AD/AB
AD/AB=12/18=2/3
Therefore AL/AM=2/3
AL= 6.4cm
Therfore AM=9.6cm
length of AM =9.6cm
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