Question

In a parallelogram ABCD, AB=20cm and AD=12cm.The bisector of angle A meets DC at E and BC produced at F. Find the length of CF.​

Answer 1

draw a line TF parallel to AB.

such that T lies on the extended AD.

ABFT is also a parallelogram

given AF bisects angle A

let <TAF and<BAF = x

as TA is parallel to BF

<BFA =<TAF

<BFA=<BAF

triangle ABF is an isosceles triangle.

BF=AB=20

CF=BF-BC=20-12=8

hence CF =8 cm.

please Mark it as brainliest.