Question

In a parallelogram ABCD,AB=4 cm,BC=7cm,Each of its diagonals is less than----(A)5 cm;(B)6 cm;(C)7 cm;(D)11 cm.​

Answer 1

Answer:

D)11

(A,+B)>c

and the parallelogram with two sides and 1diagonal becomes a triangle

Answer 2

Each of its diagonals is less than (D) 11 cm.

Given,

In a parallelogram ABCD, AB=4 cm and BC=7cm.

To Find,

Each of its diagonals is less than?

Solution,

We can solve the question as follows:

It is given that in a parallelogram, the sides AB and BC are equal to 4 cm and 7 cm, respectively. We have to find each of its diagonals is less than what value.

$AB = 4\: cm$

$BC = 7\: cm$

Now,

In a parallelogram ABCD, the diagonal AC should be less than the sum of the sides AB and BC.

$AC < AB + BC$

Substituting the values in the above formula,

$AC < 4 + 7$

$AC < 11\: cm$

Hence, each of its diagonals is less than (D) 11 cm.

#SPJ3