Question

In a parallelogram ABCD AB = 72 cm and the perpendicular from C on AB is 45 cm
TRIANGLE​

Answer 1

Step-by-step explanation:

Area of the parallelogram ABCD = (base)(height) = (CD)(AP) = 72 sq.cm.

Area of the parallelogram ABCD = (base)(height) = (CD)(AP) = 72 sq.cm.(CD)(AP) = 72 9(AP) = 72 => AP = 8

Area of the parallelogram ABCD = (base)(height) = (CD)(AP) = 72 sq.cm.(CD)(AP) = 72 9(AP) = 72 => AP = 8DP=√AD2−AP2=√162−82=8√3

Area of the parallelogram ABCD = (base)(height) = (CD)(AP) = 72 sq.cm.(CD)(AP) = 72 9(AP) = 72 => AP = 8DP=√AD2−AP2=√162−82=8√3Area of triangle

Area of the parallelogram ABCD = (base)(height) = (CD)(AP) = 72 sq.cm.(CD)(AP) = 72 9(AP) = 72 => AP = 8DP=√AD2−AP2=√162−82=8√3Area of triangle APD=12

Area of the parallelogram ABCD = (base)(height) = (CD)(AP) = 72 sq.cm.(CD)(AP) = 72 9(AP) = 72 => AP = 8DP=√AD2−AP2=√162−82=8√3Area of triangle APD=12(AP)

Area of the parallelogram ABCD = (base)(height) = (CD)(AP) = 72 sq.cm.(CD)(AP) = 72 9(AP) = 72 => AP = 8DP=√AD2−AP2=√162−82=8√3Area of triangle APD=12(AP)(PD)=32√3