in a parallelogram ABCD, AB is equal to 18 cm, BC is equal to 12 CM.AE perpendicular to DC, AF perpendicular to BC and if AE=6.4cm, find the length of AF.
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Answer:
9.6 cm
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Base, AB = 18 cm
Height, AL = 6.4 cm
∴ Area of the parallelogram ABCD = Base × Height
= (18 cm × 6.4 cm) = 115.2 cm2 ... (i)
Now, taking BC as the base:
Area of the parallelogram ABCD = Base × Height
= (12 cm × AM) ... (ii)
From equation (i) and (ii):
12 cm × AM = 115.2 cm2
⇒ AM = 115.212cm
= 9.6 cm
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