Question

in a parallelogram ABCD ab is equal to 4√ 3 cm and BC is equal to 10 cm and angle d is equal to 60 degree find the area of the parallelogram ABCD​

Answer 1

3 root and 40 because area of llgm b×h so,you will multiple then you will get this.....

Answer 2

The area of the given parallelogram is $60cm^{2}$.

Given,

In a parallelogram ABCD,

$AB=4\sqrt{3} cm$

$BC=10cm$

∠$D=60$°

To find,

Area of the parallelogram ABCD.

Solution,

Let us draw a perpendicular on AD.

Now,

In ΔCDY,

∠$Y=90$°

∠$D=60$°

So, with the help of the trigonometric ratio,

$sin\alpha =\frac{Perpendicular}{Hypotenuse}$

⇒$sin60=\frac{CY}{CD}$

⇒$\frac{\sqrt{3} }{2} =\frac{CY}{4\sqrt{3} }$

⇒$CY=\frac{4(3)}{2}$

⇒$CY=6cm$

So, the height of the parallelogram is, $h=6cm$.

Hence, area of the parallelogram,

⇒$A=base$×$height$

⇒$A=10cm$×$6cm$

⇒$A=60cm^{2}$

Therefore, the area of the parallelogram ABCD is, $A=60cm^{2}$