Question

in a parallelogram ABCD. AN and CP are perpendiculas to BD. show that(i) ADN is similar to CBP. (ii)AN=CP​

Answer 1

Answer:

Solution:

In △ADN and △CBP

AD=CB (opposite side of parallelogram)

∠AND=∠CPB (each 90

∘

)

∠ADN=∠PBC (AD∥BC,BD is transversal) (alternate interior angles)

1. Therefore,△ADN=△CBP (ASA rule)

2. AN=CP (By cpct)

Hence proved.