in a parallelogram ABCD angle A=(3x+12) angle B=(2x-32)then find the value of x and then find the measure of angle C and angle D
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In a parallelogram ABCD angle
A=(3x+12) angle B=(2x-32)
we know,
<A + <B + <C + <D = 360°
Also,
<A + <B = 180° [ Being co-interior angles]
or, 3x + 12 + 2x - 32 = 180°
or, 5x - 20 = 180°
or, 5x = 200°
or, x = 200°/5
So, x = 40°
Now,
A=(3x+12)
= 3 x 40° + 12°
= 132°
Also,
B=(2x-32)
= 2 x 40° - 32°
= 48°
In a parallelogram ABCD
opposite angles are equal
So,<C = <A = 132°
And,
<D = <B = 48°
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