Math, asked by chandramagoswamisarm, 8 days ago

In a parallelogram ABCD, angle A=3x-20, angle B=x+25, angle C=2x+40, find the value of x ..​

Answers

Answered by dhairyasoni
2

Answer:

ok

Step-by-step explanation:

So there is a property in parallelogram which states that the opposite internal angles of a parallelogram are equal (we can prove this by joining any one diagonal of the parallelogram which will form two triangles, and then prove that the two triangles are congruent by the SSS)

hence, angle A = angle C

= 3x - 20 = 2x + 4

=  3x-2x = 20+4

=   x = 24

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