in a parallelogram ABCD angle A=(3x-60degree) and anfle B = (4b+9degree) find x and all the angles of the parallelogram
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Answer:
80°,100°,80°,100° are the angles of the parallelogram
Step-by-step explanation:
Given, in a parallegram ∠A = 3x-4 & ∠B = 3x+16 (check your question)
we know that, in a ║gm, the sum of adjacent angles = 180°
=> ∠A + ∠B = 180°
=> 3x-4° + 3x+16° = 180°
=> 6x+12° = 180°
=> 6x = 180° - 12°
=> 6x = 168°
=> x = 168°/ 6
=> x = 28°
Now,
∠A = (3x - 4)°
= (3 × 28 - 4)° = (84-4) °
= 80°
& ∠B = (3x + 16)°
= (3 × 28 + 16)°
= (84 + 16)°
= 100°
80°,100°,80°,100° are the angles of the parallelogram
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