Math, asked by xBxdNightMxrex, 28 days ago

In a parallelogram ABCD, angle A= 3yº, angleB =(2y-5) and angle C= ( 3x + 3)". Find the value of x
and y.

Answers

Answered by Anonymous
5

Answer:

Two adjacent internal angles of a parallelogram are supplementary,

Therefore

∠A + ∠B = 180°

(3y) + (2y-5) = 180

3y + 2y - 5 = 180

5y - 5 = 180

5y = 185

y = 37

Opposite internal angles of a parallelogram have equal measure.

Therefore,

∠A = ∠C

3y = 3x + 3

3(37) = 3x + 3

111 = 3x + 3

108 = 3x

36 = x

Answered by kashish3367patel
2

this is the answer of that question.

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