Question

In a parallelogram ABCD, angle A=(4x+20)°, angle B=7yº, angle D={6x+3y-8)°. Find the values of x and y.​

Answer 1

$angle \: a \: + angle \: b = 180$

$4x + 20 + 7y = 180$

$4x + 7y = 180 - 20$

$4x + 7y = 160$

$angle \: b = angle \: d$

$7y = 6x + 3y - 8$

$8 = 6x - 4y$

$4 = 3x - 2y$

$3x - 2y = 4$

$12x + 21y = 480$

$12x - 8y = 16$

$29y = 464 = 16$

$3x - 2y = 4$

$3x - 32 = 4$

$3x = 4 + 32$

$3x = 36$

$x = \frac{36}{3}$

$x = 12$

$y = 16$

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Answer 2

Answer:

above is correct thank you