Question

In a parallelogram ABCD ,angle A=(4x-5) and angle C=(3x+10). find angle A and angle B.

Answer 1

Hi,

Here's ur answer:-

Being the opposite sides, A & C are equal.

So,

(4x-5) = (3x+10)

=> 4x-3x = 10+5

=> x = 15

So the angle is 4x - 5 = 4×15 - 5 = 60-5=55°

So, B & D are also equal.

Their values are:-

(180°-55°)=125°

HOPE IT HELPED (^_^)

Answer 2

hi friend
here's your answer looking for

if A= 4x-5
and,
C= 3x+10

so,

angle A= angle C. ( opposite angles of parallelogram )

so,

$(4x - 5) = (3x + 10) \\ \\ 4x - 3x = 10 + 5 \\ \\ x = 15$
now,

Angle A = 4x-5

=4(15)-5

=60-5

=55

and,

angle A + angle B = 180

55+ angle B = 180

angle B = 125

hope you are satisfied with my answer