Math, asked by cjsiedmiorka, 10 months ago

In a parallelogram ABCD ,angle A=(4x-5) and angle C=(x+15). find angle A and angle B.

Answers

Answered by nikpanda
0

Answer:

angle A = 65/3

angle B = 475/3

Step-by-step explanation:

In a parallelogram ABCD,

angle A = angle C

angle B = angle D

and angle A + angle B = 180.

So, according to the question,

angle A = 4x - 5

angle C = x + 15

=> 4x - 5 = x + 15

=> 3x = 20

=> x = 20/3

angle A = 65/3

angle B = 180 - 65/3

=> angle B = 475/3

Answered by ashishchackooom
0

Answer:

parallelogram ABCD

angle A = 4x - 5

angle C = x +15

angle A = angle C (OPPOSITE ANGLE OF AN PARALLELOGRAM ARE EQUAL)

x + 15 = 4x - 5

15 + 5 = 4x - x

20 = 3x

x =20/3

x = 6.666

angle A= 4(6.666)- 5

angle C = 6.6666 -5

angle A=angle C=1.6666

angle A + angle B =180 degree (linear pair)

angle B = 178. 44444

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