In a parallelogram ABCD ,angle A=(4x-5) and angle C=(x+15). find angle A and angle B.
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Answered by
0
Answer:
angle A = 65/3
angle B = 475/3
Step-by-step explanation:
In a parallelogram ABCD,
angle A = angle C
angle B = angle D
and angle A + angle B = 180.
So, according to the question,
angle A = 4x - 5
angle C = x + 15
=> 4x - 5 = x + 15
=> 3x = 20
=> x = 20/3
angle A = 65/3
angle B = 180 - 65/3
=> angle B = 475/3
Answered by
0
Answer:
parallelogram ABCD
angle A = 4x - 5
angle C = x +15
angle A = angle C (OPPOSITE ANGLE OF AN PARALLELOGRAM ARE EQUAL)
x + 15 = 4x - 5
15 + 5 = 4x - x
20 = 3x
x =20/3
x = 6.666
angle A= 4(6.666)- 5
angle C = 6.6666 -5
angle A=angle C=1.6666
angle A + angle B =180 degree (linear pair)
angle B = 178. 44444
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