IN A PARALLELOGRAM ABCD,ANGLE A=70*(*=DEGREE);FIND ALL THE OTHER ANGLES....
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Opposite angles are equal so one of the three missing angles is 70°. Sum of all angles of parallelogram is 360°. Let the 2 missing angles be x.
So
70+70+x+x=360
140+2x=360
2x=370-140
2x=230
x=115
Hence, the remaining two angles measure 115° each.
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