Question

in a parallelogram ABCD angle A is 30 degree more than Angle B find the measure of all the angles ​

Answer 1

Let angle B = x.

Sum of angles = 180[because adjacent angles are supplementary]

=> A + B = 180

=> (30 + x) + x = 180

=> 30 + 2x = 180

=> x = 75.

Hence,

<A = 30 + 75 = 105

<B = 75

<C = 105

<D = 75

#BeBrainly

Answer 2

The measure of all the angles would be 75°,105°,75°,105°

Step-by-step explanation:

Since ABCD is a parallelogram.

So, opposite angles are equal.

i.e. ∠A = ∠C

∠B = ∠D

Let the measure of ∠B be 'x'

Let the measure of ∠A be 'x+30'.

As we know that AC is parallel to BD.

So, sum of adjacent angles must be supplementary.

So, ∠A + ∠B = 180°

$30+x+x=180^\circ\\\\30+2x=180^\circ\\\\2x=1806\circ*30^\circ\\\\2x=150^\circ\\\\x=\dfrac{150}{2}\\\\x=75^\circ$

So,  ∠B = ∠D = 75°

and  ∠A = ∠C = 30+75 = 105°

Hence, the measure of all the angles would be 75°,105°,75°,105°.

# learn more:

Find the measure of all the angles of parallelogram ABCD, if angle D is 60degree.​

https://brainly.in/question/10169773