Question

in a parallelogram ABCD angle ACD equal to 50 degree and angle ADC is equal to 60 degree find the magnitude of angle ABC and ACB please answer​

Answer 1

since it is a //gm,

ab//cd ,AD is a transversal.

given:ang ADC=60°

so,angle DAB=60°(due to alt. int. angle)

in ∆ACD,

angle CAD =60°+50°=180°

x=180°-110°=70°

angle C= angle B ( beause opposite angle side of a //gm is equal.

angle B =50°

we know that in //gm diagonals are perpendicular to each other.

so, angle AOB=90°

in ∆ AOB,

angle(BAD+AOB+ABC )=180°

angle(60°+90°+ABC)=180°

angle ABC= 180°-150°= 30°

angle BCD = 30°(due tu alt.int.angle)

angle ACB=30°+x=50°

x=50°-30°=20°

hope this helps you

sorry i took many times

because my camera was not good and typing takes a lot of time.

reply is my answer right or wrong

Answer 2

Answer:

ABC =angle ADC = angle ABC

angle adc= 60 degree

angle ABC = 60 degree ( opposite angle of parallelogram are equal)