Question

In a parallelogram ABCD,angle B=(4x-5)° and angle D=(3x+10)°. Calculate angle B and angle C​

Answer 1

Step-by-step explanation:

In parallelogram PQRS,

∠Q = (4x – 5)° and ∠S = (3x + 10)°

opposite ∠s of //gm are equal.

∠Q = ∠S

4x – 5 = 3x + 10

4x – 3x = 10 + 5

x = 15

∠Q = 4x – 5 =4 x 15 – 5 = 55°

Also ∠Q + ∠R = 180°

55° + ∠R = 180°

∠R = 180°- 55° = 125°

∠Q = 55° ; ∠R = 125°

Answer 2

Step-by-step explanation:

We know that, opposite angles of a parallelogram are equal.

∴ ∠Q=∠S

⇒ 4x−5=3x+10

⇒ 4x−3x=10+5

⇒ x=15

⇒ ∠Q=(4x−5) ° =(4×15−5) °

=55 °

We know that, sum of adjacent angles of parallelogram is 180 °

⇒ ∠Q+∠R=180 °

⇒ 55 +∠R=180 °

∴ ∠R=125°