in a parallelogram ABCD, angleA = 60digrees what will be the measur of angleD
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In paralellogram ABCD
∠A = ∠C = 60
∠B = ∠D
∠A + ∠B + ∠C + ∠D = 360
120 + 2∠D = 360
2∠D = 360 - 120
2∠D = 240
∠D = 240 / 2
∠D = 120°
∠A = ∠C = 60
∠B = ∠D
∠A + ∠B + ∠C + ∠D = 360
120 + 2∠D = 360
2∠D = 360 - 120
2∠D = 240
∠D = 240 / 2
∠D = 120°
purvisri02:
no
ABCD paralellogram is in order
but it is in order
otherwise it would be ABDC
welcome
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