in a parallelogram ABCD,angleD=75 degree, find the measure of other 3 angles
hulra12345:
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Answered by
67
Hi Mate!!
//gm :-
1). Opposite sides are equal.
2). Opposite angles are equal.
3). Diagonals bisects each other and are
unequal.
4). Sum of all angles = 360°
Exp:-
A + B + C + D = 360°
=>. A = C and B = D
=>. 2 A + 150 = 360
=>. A = 105°
So, the other three angles are 105°, 75 and 105°
Have a nice time
//gm :-
1). Opposite sides are equal.
2). Opposite angles are equal.
3). Diagonals bisects each other and are
unequal.
4). Sum of all angles = 360°
Exp:-
A + B + C + D = 360°
=>. A = C and B = D
=>. 2 A + 150 = 360
=>. A = 105°
So, the other three angles are 105°, 75 and 105°
Have a nice time
Answered by
67
It is given that in a //gm ABCD in which ∠D = 75°.
To find the measure of :- ∠A , ∠B and ∠C.
Since opposite angles of //gm are equal.
•°• ∠B = ∠D = 75°
we know that any sum of two adjacent angles of //gm is 180°.
∠A + ∠B = 180°
=> ∠A + 75° = 180°
=> ∠A = 180° - 75°
=> ∠A = 105°
Since opposite angles of //gm are equal.
•°• ∠A = ∠C = 105°
Hence , the measures of ∠A = 105° , ∠B =75° and ∠C = 105°.
To find the measure of :- ∠A , ∠B and ∠C.
Since opposite angles of //gm are equal.
•°• ∠B = ∠D = 75°
we know that any sum of two adjacent angles of //gm is 180°.
∠A + ∠B = 180°
=> ∠A + 75° = 180°
=> ∠A = 180° - 75°
=> ∠A = 105°
Since opposite angles of //gm are equal.
•°• ∠A = ∠C = 105°
Hence , the measures of ∠A = 105° , ∠B =75° and ∠C = 105°.
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