in a parallelogram ABCD,angleDAB=40° find the other angles of the parallelogram
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Given: ∠DAB=∠BCD=40 degree and AD∥BC
We know that the sum of consecutive angle are 180 degree
∠CBA+∠DAB=180 degree
∴∠CBA=180−40=140 degree
We know that in parallelogram opposite angles are equal.
Therefore, ∠ADC=∠CBA=140 degree
So angles of parallelogram are 40 degree ,140 degree ,40 degree ,140 degree
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