Question

In a parallelogram ABCD, AP and CQ are perpendicular drawn to the diagonal BD. On measuring it is found that ∠PAB = 65° and ∠DAB = 75°, then the measure of ∠QCD is​

Answer 1

Answer:

80°

there u go !!

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Answer 2

Answer:

The measure of ∠QCD in the parallelogram ABCD is 65°.

Step-by-step explanation:

From the above question,

They have given :

  In a parallelogram ABCD, AP and CQ are perpendicular drawn to the diagonal BD. On measuring it is found that ∠PAB = 65° and ∠DAB = 75°

ABCD is a parallelogram. AP and CQ are perpendicular lines drawn from vertices A and C respectively on  diagonal BD.

To show : ΔAPB≅ΔCQD

Proof:

In triangle APB and triangle  CQD.

AB=CD (Opposites sides of parallelogram)

∠ABP=∠CDQ ( Alternate interior angles)

∠APB=∠CQD=90∘ (Given )

Thus,

    The measure of ∠QCD in the parallelogram ABCD is 65°.

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