Question

In a parallelogram ABCD, AP and CQ are perpendicular drawn to the diagonal BD. On
measuring it is found that angle PAB=55° and angle DAB = 85°, then the measure of angle QCD and angle
CDB.​

Answer 1

Answer:

given- ABCD is parallelogram

            AP & CQ are perpendicular drawn to the diagonal BD

           PAB=55° and angle DAB = 85°,

Step-by-step explanation:  

      angle DAB = angle DAP + angle PAB

                    85          =       angle DAP + 55

           85-55 =30 = angle DAP _ 1

     in triangle apb

    angle a = 55

    angle p = 90

    angle b = to find

             a+p+b =180  ........ angle sum properti

            55+90+ b= 180

           145 -180= b

            b = 35  ...... 2

         from  2   angle ABP = 35 = ABD

       therfore - ANGLE ABD =angle BDC ... opposite angles of                                                                parllelogram  

     in triangle DCQ

     angle D =35

     angle Q = 90

    angle C = to find

      35 +90+ c =180

    125 -180 = 55

       finely qcd =55

                cdb =35