In a parallelogram ABCD, CO and DO are angle bisectors of ∠C and ∠D respectively. Then ∠COD = 1/2 ----------
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Answer=⟩In △COD,
∠COD+∠1+∠2=180
o
∠COD=180
o
−(∠1+∠2)
∠COD=180
o
−
2
1
(∠C+∠D)
∠COD=180
o
−
2
1
[360
o
−(∠A+∠B)]
∠COD=
2
1
(∠A+∠B)
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