Math, asked by moumita182006, 9 months ago

In a parallelogram ABCD, CO and DO are angle bisectors of ∠C and ∠D respectively. Then ∠COD = 1/2 ----------​

Answers

Answered by rohit6284921917
2

Answer=⟩In △COD,

∠COD+∠1+∠2=180

o

∠COD=180

o

−(∠1+∠2)

∠COD=180

o

2

1

(∠C+∠D)

∠COD=180

o

2

1

[360

o

−(∠A+∠B)]

∠COD=

2

1

(∠A+∠B)

solution

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