Math, asked by sheebabyju09, 18 days ago

in a parallelogram ABCD ΔD = 150° determine AB and C​

Answers

Answered by manoharb28
0

Answer:

please Mark me as brainliest

Attachments:
Answered by Himanshichaudhary2
0

Answer:

In parallelogram ABCD, ∠A and ∠C are opposite angles.

We know that in a parallelogram, the opposite angles are equal.

Therefore,

∠C = ∠A

We have ∠A = (3x - 20°) and ∠C = (x + 40°)

Therefore,

x + 40° = 3x - 20°

x - 3x = -40° - 20°

-2x = - 60°

x = 30°

Therefore,

∠A = (3x - 20°)

∠A = [3(30) - 20°]

∠A = 70°

Similarly,

∠C = 70°

Also, ∠B = ( y + 15)°

Therefore,

∠D = ∠B

∠D = (y + 15 )°

By angle sum property of a quadrilateral, we have:

∠A + ∠B + ∠C + ∠D = 360°

70° +(y + 15)° + 70° + (y + 15)° = 360°

140° + 2 (y + 15)° = 360°

2(Y + 15)° = 360° - 140°

2(y + 15)° = 220°

(y + 15)° = 110°

y = 95°

Hence the required values for x and y are 30° and 95° respectively.

Similar questions