In a parallelogram ABCD, DE is perpendicular to AB, BE = 4 cm and CD = 8 cm. Find the perimeter of ADE, if area of parallelogram is 24 cm. sq
pls tell me steps and diagram don't tell me answer
Answers
Answer:
Given, AB=8cm;BC=4cm
Perpendicular distance between AB and BC is DL=3cm
The area of the parallelogram =base×height
=AB×DL
=8×3=24cm
2
Area of the parallelogram =base×height
=AD×BM
24=4×height
Height=6cm
So the perpendicular distance between AD and BC is 6cm
Answer:
Given, AB=8cm;BC=4cm
Perpendicular distance between AB and BC is DL=3cm
The area of the parallelogram =base×height
=AB×DL
=8×3=24cm
2
Area of the parallelogram =base×height
=AD×BM
24=4×height
Height=6cm
So the perpendicular distance between AD and BC is 6cm