Question

in a parallelogram ABCD diagonals AC and BD bisect each other prove it

Answer 1

Answer:

In a parallelogram ABCD, let diagonals AC and BD intersect at O.

then

angle AOD = angle BOC

AD = BC                                   (opposite sides of a parallelogram are equal)

angle CBD = angle ADB         (alternate angles are equal in a parallelogram

then

triangle AOD will be congruent  triangle BOC (by AAS or ASA criteria)

then

AO = OC                [ by C.P.C.T (corresponding parts of congruent triangles) ]

BO = OD                [ by C.P.C.T (corresponding parts of congruent triangles) ]

NOW.....      AO = OC ; BO = OD

SO WE CAN SAY THAT DIAGONALS OF A PARALLELOGRAM BISECTS EACH OTHER.

HOPE THIS WILL HELP YOU OUT OF THIS PROBLEM